4n^2+-13n+8=0

Solution for 4n^2+-13n+8=0 equation:

4n^2+-13n+8=0

We add all the numbers together, and all the variables

4n^2-13n=0

a = 4; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·4·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*4}=\frac{0}{8}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*4}=\frac{26}{8}
=3+1/4
$